Cleveland 2023

Q1

D1 D2 D3 D4 D5 D6 D7

martedì 31 gennaio

T1

Diallo G [8]

b.

Ayeni A

6/1, 6/1

T1

Kozlov S [6]

b.

Kypson P [Alt]

6/4, 7/6⁸

T1

Sandgren T

b.

Ejupovic E

6/2, 6/7⁴, 7/6⁴

T1

Michelsen A [WC]

b.

Sock J [4]

7/6³, 6/4

T1

Johnson S [3]

b.

Forejtek J

6/4, 7/6²

T1

Kirchheimer S

b.

Zhu E

6/2, 7/5

T1

Marchenko I

b.

Kodat T [Q]

7/5, 5/7, 6/3

T1

Svajda Z

b.

Pecotic M [Q]

6/1, 6/2

T1

Wu Y [2]

b.

Mayo A [Q]

6/1, 0/6, 6/4

T1

Holt B [7]

b.

Perez A [Q]

6/4, 6/2

T1

Harrison R [Q]

b.

Angele J [Q]

6/2, 6/1